3x+x-4=x^2+6x+2

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Solution for 3x+x-4=x^2+6x+2 equation: 



3x+x-4=x^2+6x+2

We move all terms to the left:

3x+x-4-(x^2+6x+2)=0

We add all the numbers together, and all the variables

4x-(x^2+6x+2)-4=0

We get rid of parentheses

-x^2+4x-6x-2-4=0

We add all the numbers together, and all the variables

-1x^2-2x-6=0

a = -1; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·(-1)·(-6)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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